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OpenStudy (lovelyharmonics):
f(x)=-4x^2+11x at x=10
OpenStudy (neer2890):
just put 10 inplace of x.
find f(10)
OpenStudy (lovelyharmonics):
really? its that freaking simple?
OpenStudy (anonymous):
you have to differentiate it, right?
OpenStudy (lovelyharmonics):
differentiate what c:
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OpenStudy (lovelyharmonics):
it just says find the derivative
OpenStudy (anonymous):
you said derivate on top
OpenStudy (anonymous):
uh huh
OpenStudy (lovelyharmonics):
no i didnt XD
OpenStudy (anonymous):
lovelyharmonics
more derivatives....
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OpenStudy (lovelyharmonics):
yeah but i didnt say derivate...
OpenStudy (lovelyharmonics):
can you help :c
OpenStudy (anonymous):
so you are not supposed to take derivative of
f(x)=-4x^2+11x at x=10?
OpenStudy (lovelyharmonics):
/).(\ i dont know. my entire question is find the derivative...... insert equation here
OpenStudy (anonymous):
well
then find derivative of -4x^2+11x
like the formula hartnn had told
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OpenStudy (kirbykirby):
I'm assuming you find the derivative first, then plug in x = 10
OpenStudy (anonymous):
yep
OpenStudy (lovelyharmonics):
why cant it just be easy :c
OpenStudy (kirbykirby):
\(f(x) = -4x^2+11x\)
derivative:
\(f'(x)=-4(2)x+11=-8x+11\)
plug in x = 10:
\(f'(10)=-8(10)+11=-80+11=-69\)
OpenStudy (lovelyharmonics):
wait wheres the fractions.... its d/dx x^n
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OpenStudy (kirbykirby):
\[ f'(x)=\frac{d}{dx}f(x)\]
OpenStudy (lovelyharmonics):
nuuuu.... it was \[\frac{ d }{ dx }x^n\]
OpenStudy (kirbykirby):
Is the question finding the derivative of \(x^n\) or \(-4x^2+11x\) ?
OpenStudy (lovelyharmonics):
find the derivative of f(x)=-4x^2+11x at x=10
OpenStudy (kirbykirby):
Well ok, that is the answer above that I wrote...
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OpenStudy (kirbykirby):
maybe you're wondering how to use the power rule??
\[ \frac{d}{dx}x^n = nx^{n-1}\]
for \(x^2\), \(n=2\) so \[ \frac{d}{dx}x^2=2x^{2-1}=2x^1=2x\]
That is how I got from \(-4x^2\) to \(-4(2)x\)... but of course, you ignore the coefficient -4 in front