Question

limits

Answer 1

\[\lim_{x \rightarrow -2} \frac{ x^2-4 }{ x+4 }\]

Answer 2

simply plugin x = -2

Answer 3

\[\large \lim_{x \rightarrow -2} ~\frac{ x^2-4 }{ x+4 }\]

\[\large~~~~\frac{ (-2)^2-4 }{ -2+4 }\]

Answer 4

simplify

Answer 5

4-4=0/2 so it does not exist?

Answer 6

\[\large \dfrac{0}{2} = 0\]

\[\large \dfrac{2}{0} = DNE\]

Answer 7

0/2 = 0

the limit exists, the value is 0 !

Answer 8

having 0 in the numerator is fine, but 0 is not allowed in the denominator

Answer 9

oh .-. makes sense im learning limits!

Answer 10

I see... derivatives will be more fun :)
Enjoy... !