Help please.. The function f(t) = 3 cos(pi over 6t) + 5 represents the tide in Blastic Sea. It has a maximum of 8 feet when time (t) is 0 and a minimum of 2 feet. The sea repeats this cycle every 12 hours. After nine hours, how high is the tide? 12 feet 5 feet 4.5 feet 2.5 feet
@zepdrix
@jim_thompson5910
So they just want us to evaluate this function at t=9 hours.\[\Large\rm f(\color{orangered}{t})=3\cos\left(\frac{\pi}{6}\color{orangered}{t}\right)+5\]\[\Large\rm f(\color{orangered}{9})=3\cos\left(\frac{\pi}{6}\color{orangered}{9}\right)+5\]
Looks like the inside simplifies a lil bit,\[\Large\rm f(9)=3\cos\left(\frac{9\pi}{6}\right)+5\]\[\Large\rm f(9)=3\cos\left(\frac{3\pi}{2}\right)+5\]Do you remember your unit circle? :O cos(3pi/2) = ?
I do not.. I can put it into Mathway if you like :oo
You... -_- Yah do that then :p throw it into a calculator, you should get a nice simple answer.
0 correct?
yes. good.
Whoop ^.^
\[\Large\rm f(9)=3\cdot0+5\]
so f(9)=5
yay good job \c:/
And that's my answer ^.^ Thank you!!
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