Help? Let f(x) = -4x + 7 and g(x) = 2x - 6. Find \((g ° f)(1)\).
@hartnn
I don't know what the degree sign is supposed to mean..
\((g ~o~f )(x)\) is read as "g of f of x" it is a composition of functions g and f
Oh, so I'm supposed to multiply the functions?
to find \(g(f(1))\) you can also start this by directly finding f(1)
f(1) is the value of f(x) when x =1
Isn't f(1) the same?
f(x) = -4x + 7 plug in x =1 here you will get f(1)
f(x) = -4x + 7 f(x) = -4(1) + 7 f(x) = -4 + 7 f(x) = 3
Oh, now what do I do?
f(x) = -4x + 7 f(1) = -4(1) + 7 f(1) = -4 + 7 f(1) = 3
ok, now we have f(1) =3 \(\Large g(f(1))= g(3)\)
so you just need g(3) to find g(3), plug in x = 3 in g(x)
Oh. \(g(x) = 2x - 6\) \(g(3) = 2(3) - 6\) \(g(3) = 6 - 6\) \(g(3) = 0\) Is that correct?
\(\huge \checkmark\)
Awesome, didn't know it was that easy.
:)
How do you make that check? @hartnn
type this `\(\huge \checkmark\)` that \checkmark is for the check \huge is to make the font very big
\(\huge \checkmark)
Oops, forgot the last slash
\(\huge \checkmark\)
Got it, thanks
\(\Large Good ~ work ~ \ddot \smile \)
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