Electron configuration of chromium
s-blocks consists of 2 grps.. Grp 1(s^1) & 2(s^2) p-block consists of metals,metalloids n non-metals Grp 13 n Grp 18 d-block consists of 3 series of metals..each series has 10 elements wth electronic configuration f-block consist of 2 series of metals known as lanthanides n actinides @Somy
okay
so u understood about S block right?
yup
nice P block as we said its gr 3-8
what happens is that before actually going to P block S block has to be filled first
S block takes up to 2 electrons and P block takes up to 6 electrons
if we take Mg as an example
its atomic number is 12 so it's 12th element of periodic table
ok
so how many electrons does it have in total?
12
cool as you said in total Mg has 12 electrons now the question is Where are they?
lets start looking at each element before Mg
period 1 first element is H
ok..
so H is in group 1 right?
ys
what block is group 1
s-block is it 1s^1
thats right so S block is filled with 1 electron only
now its He
it has in total 2 electrons
both in the same shell and as we said the one's first to fill up would be S block
this number 1 in 1s^ shows that its shell 1 so if He has 2 electrons in total, both will be in S block right?
but He is in Grp 18..shld be p-block It's a noble gas
yeah but its same shell first to fill up is always S orbital
okay
okay so first period has 2 elements thus 2 electrons
both electrons will go to S orbital
thus its 1s^2
next moving down to next period period 2 has 8 elements thus 8 electrons
again first filling will be S orbital thus first 2 electrons (from gr 1 and gr 2) will go to S orbital so now it'll be 1s^2, 2s^2
get it so far?
yes
cool after S orbital is filled we start filling P orbital
so as u reach 3rd element/electron in period 3 your S orbital gets 2, but 1 is left, where is it?
it starts going to P orbital so now P orbital takes that 1 electron thus now the configuration looks like this 1s^2, 2s^2 2P^1
r u catching up?
ys
okay so next is 4th electron
it again goes to P orbital so now p orbital has 2 electrons so 1s^2, 2s^1 2p^2
ok
next its 5th and 6th and 7th and 8th electrons
all go to p orbital
now it becomes like this 1s^2, 2s^2 2P^6
right?
yes
so by the end of period 2 P orbital is filled
because it can take up to 6 electrons and it got it
okay so by this period 2 is done
now we go down to next period period 3
that means there will be a new shell right?
yes
so as the new shell starts we have to start with subshells meaning S and P orbitals right? and the first one to start filling will be S orbital
so period 3 group 1 meaning 1 electron in its last shell - shell 3
that 1 electron will go to S orbital
right?
ys
so can u tell how is the electronic configuration for Na going to look like?
2.8.1 1s^1 2s^2 2p^6 3s^1
as u should be getting now is that we consider the electrons before reaching the last shell Na has in total 11 electrons, and as we know 1 of this electrons is going to be in last shell s orbital, what about other 10 electrons? thus u've gotta show the whole configuration and YAY good job :)
if the question asks u for Last shell configuration only u can say 3s^1 because as long as u show 3 that means the element is in period 3 and s^1 shows that the element is in S block meaning it has 1 electron in its last shell thus No doubt that its Na
okay
now i see u r getting it quite well now can u tell show configuration of Mg on ur own?
lmao show*
2.8.2 1s^2 2s^2 2^6 3s^2
goooooood :) now do it for Ar
2.8.8 1s^2 2s^2 2p^6 3s^2 3p^6
now for Ca
2.8.8.2 1s^2 2s^2 2p^6 3s^2 2p^6 4s^2 I'm nt sure
thats right!!
next the pain stars
and its D block
wait
yeah?
so, 4s comes before 3d
exactly
thats because energy level of 4s is relatively lower then of 3d
because it's nearer to the nucleus gt it!
thats why now as u reach D block of transition elements S and P orbitals basically freezes thats why no electron will go to P orbital of 4p and next set of electrons will go to d orbital
it will not YET go there because D orbital can take up to 10 electrons
once it gets all 10 electrons, we can go to 4P orbital then
okay so everything works as i taught u just now for S and P orbitals filling
can u try writing electronic configuration of V ?
2.8.8.5 I don't know
okay look
look at first transition element its Sc right?
yes
so what was electronic configuration for the element before this transition one meaning of Ca
2.8.8.2 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2
good so what we said is that now we start filling 3d orbital and we don't touch other orbitals till it gets all its 10 electrons right?
Sc, first transition element so its last electron will go to 3d shell thus it'll be 3d^1 do u agree?
why 3d^1 , why shld be 1
because Sc is actually in group 3 and that means 2 of electrons is taken by S orbital
since d orbital of transition element is pretty greedy thats why it doesn't let P orbital to take the left out 1 electron and so d orbital takes it to itself
okay
and it keeps on doing it till it gets all 10 electrons to itself
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