Question

the question is below

Answer 1

if\[\left[\begin{matrix}4 & 2y-1 \\ 27 & 6\end{matrix}\right] = \left[\begin{matrix}4 & 5 \\ 9^{3x-y} & 6\end{matrix}\right]\]
the value of y-x =?

Answer 2

Your idea?

Answer 3

is it 2y-1=5 then \[27 = 9^{3x-y}\]
m i ryte??

Answer 4

u r ryte, hahahaha... what kind of English you use. !!!
then solve for y and x

Answer 5

hahaha short form!!! to find x should i substitute the value of y i find earlier?

Answer 6

x=3/2 and y=3

Answer 7

@sid0830 can you show me the solution??

Answer 8

you have it, 2y-1=5 implies y = 3
9^(3x-3)=27 implies 3x-3 = log_9(27) solve for x

Answer 9

x i got 3/2 !! y-x=3/2 @zzr0ck3r :)