Physics
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OpenStudy (anonymous):
A car’s headlight dissipates 40 W on low beam and 50 W on high beam. Is there more or less resistance in the high-beam filament?
@Abhisar
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OpenStudy (abhisar):
What's ur say ?
OpenStudy (anonymous):
i would say there is less resistance because it is putting out more watts
OpenStudy (abhisar):
brb
OpenStudy (abhisar):
i am back
OpenStudy (abhisar):
u know the formula for power ?
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OpenStudy (abhisar):
it's
\[P = \frac{ V^{2} }{R}\]
OpenStudy (abhisar):
Now can uh predict the answer using this ?
OpenStudy (abhisar):
the formula says that power is inversly proportional to the resistance
OpenStudy (abhisar):
i.e if power increases resistance decreases
OpenStudy (abhisar):
Now predict the answer !
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OpenStudy (abhisar):
???????
OpenStudy (anonymous):
ok i'm here i walked away
OpenStudy (anonymous):
explain the formula again please
OpenStudy (abhisar):
p = power, v = voltage, R = resistance
OpenStudy (anonymous):
P= 40\[P=40^2 /r\]
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OpenStudy (anonymous):
?
OpenStudy (abhisar):
No actually u dont need to calculate anything...
OpenStudy (abhisar):
the formula says that power is inversly proportional to the resistance
OpenStudy (abhisar):
i.e if power increases resistance decreases
OpenStudy (anonymous):
so i was right the first time?
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OpenStudy (abhisar):
More the power of bulb, lesser will be resistance
OpenStudy (abhisar):
Yes uh r ryt !