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Mathematics 21 Online
OpenStudy (australopithecus):

Find the matrix A https://i.imgur.com/GH3K93s.png How do I solve this?

ganeshie8 (ganeshie8):

\(\large (A^{-1})^T = (A^T)^{-1}\)

ganeshie8 (ganeshie8):

may be work it out by undoing the operations - start by taking the transpose both sides

ganeshie8 (ganeshie8):

\[ \left(5A\right)^T = \left[ \begin{array}{cc} 2&-3 \\ -1&4 \\ \end{array} \right]^{-1} \]

ganeshie8 (ganeshie8):

\[ 5A = \left[ \begin{array}{cc} 2&-1 \\ -3&4 \\ \end{array} \right]^{-1} \]

OpenStudy (australopithecus):

How do I deal with the inverse in this problem?

OpenStudy (australopithecus):

the answer is, https://i.imgur.com/Uvkdxz3.png

OpenStudy (australopithecus):

so I assume I cant just divide both sides by 1/5

ganeshie8 (ganeshie8):

why not... 5A = t means A = t/5 right

OpenStudy (australopithecus):

I mean to get the answer

OpenStudy (australopithecus):

Can I just take the inverse of the inverse on the right to get the answer?

ganeshie8 (ganeshie8):

\[A = \dfrac{1}{5} \left[ \begin{array}{cc} 2&-1 \\ -3&4 \\ \end{array} \right]^{-1}\]

ganeshie8 (ganeshie8):

yes just take the inverse

OpenStudy (australopithecus):

Ok thats what I suspected, I make so many arithmetic errors its probably why I didnt get the correct answer in the first place

ganeshie8 (ganeshie8):

http://prntscr.com/3ugsba

OpenStudy (australopithecus):

thanks, I used the Identity algorithm for some reason

ganeshie8 (ganeshie8):

np :) btw whats an identity algorithm ?

OpenStudy (australopithecus):

Its just when you set up the augmented matrix, [A | I ] -> row operations -> [ I | A^-1 ]

ganeshie8 (ganeshie8):

aahh row operations got you :)

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