Question

solve C = 5 over 9 (F - 32) for F

Answer 1

Solve the equation for F

\(C = \dfrac{5}{9}(F - 32) \)

Answer 2

Solving for F means to isolate F.
You need F by itself.

Answer 3

The first thing to do is to get rid of the 5/9 fraction on the right side.
To do that, multiply both sides by the reciprocal of 5/9 which is 9/5.
Do that and show what you get.

Answer 4

i dont understand

Answer 5

@mathstudent55

Answer 6

@kaos_gabz

Answer 7

please help

Answer 8

Part A: Solve C = 5 over 9 (F - 32) for F. (4 points)

Part B: Determine the value of F when C = 8 °C. (2 points)

Part C: Solve –np – 80 > 60 for n. Show your work. (4 points)

Answer 9

i need all parts

Answer 10

@mathstudent55

Answer 11

@marissalovescats

Answer 12

@agent0smith

Answer 13

Ok, I'm back.

Answer 14

Part A: Solve C = 5 over 9 (F - 32) for F. (4 points)

\(C = \dfrac{5}{9}(F - 32) \)

The first step is to get rid of the 5/9, so we multiply both sides by 9/5:

\(\color{red}{\dfrac{9}{5} \cdot} C = \color{red}{\dfrac{9}{5} \cdot}\dfrac{5}{9}(F - 32) \)

\(\dfrac{9}{5} \cdot C = \dfrac{\color{red}{\cancel{9}}}{ \color{blue}{\cancel{5}} } \cdot\dfrac{\color{blue}{\cancel{5}}}{\color{red}{\cancel{9}}}(F - 32) \)

\(\dfrac{9}{5} \cdot C = F - 32 \)

Now we see that the only thing still with the F that we want to isolate is -32.
32 is being subtracted from F, so we add 32 to both sides.

\(\dfrac{9}{5} \cdot C \color{red}{+ 32} = F - 32\color{red}{+ 32} \)

\(\dfrac{9}{5} \cdot C + 32 = F \)

\(F = \dfrac{9}{5} \cdot C + 32\)