Question

Limits

Answer 1

Go on. :3

Answer 2

Take it to the limit

Answer 3

find \[\lim_{x \rightarrow 2^-}f(x) and \lim_{x \rightarrow 2^+}f(x)\]

Answer 4

The limit to '2-' means from the left of the function, to x-value 2.
'2+' means from the right of the function to x-value 2.
:3

Answer 5

i wasnt done .-. and i dont know..... my ws just shows that pic and it says
find limx->2^- and limx->2^+

Answer 6

Yeah, sorry.
So, liek, again, the limit as x approaches '2-' means as you move along the function from the left toward x-value 2, which y-value do you approach?
Can you figure that one out?

Answer 7

2^+

Answer 8

The drawing I had didn't post. .-. </3

Answer 9

Noooo, that's the other limit. :3
When we approach the x-value 2 from the left, which y-value do we approach?

Answer 10

i dont know .-. ii thought it was 2^+

Answer 11

No, that's the right hand limit. Which is which y-value does the function approach when you come from the right.

http://prntscr.com/3uigpm <--- This is another depiction of the left-hand limit.
The y-values are on the y-axis right? :3
The function approach the y-value 5, as you can see. Even if the function doesn't have a point at (2,5), it's still a limit. The limit concept is conerned with the behavior around that x-value.

Answer 12

There is a point at like, (2, 1.5) I think. But it's isolated from the rest of the graphed function. It won't be a left-hand, right-hand, or overall limit of the function.

Answer 13

wait /).(\ how do i find the limits x->2^- and x->2^+

Answer 14

.-. You look at the graph.
Again, 'limits x->2-' is saying the limit as x approaches 2 from the left hand side.
'limit x->2+' is saying the limit as x approaches 2 from the right hand side.
And the limit will be some y-value.

Answer 15

you keep sayting that but how do i answer my question .-. "use the given graph to determine the limit if it exists. find limx->2^-f(x) and limx->2^+." :c

Answer 16

Yaaaa, I showed it in my picture. /.\

Answer 17

As you move along the function from the left to x = 2, the y-value you apparoch is y = 5.
As you move along the function from the right to x = 2, the y-value you apparoch is y = -2.

Answer 18

i honestly dont even know what this question is asking .-.

Answer 19

http://prntscr.com/3uildw

Answer 20

i asked the same question yesterday and everyone said that it was impossible

Answer 21

What's impossible?

Answer 22

the whole question -.- they couldnt get it

Answer 23

.-.-. It's not impossible at all. Then, they must've not known what limits are.

Answer 24

so "As you move along the function from the left to x = 2, the y-value you apparoch is y = 5.
As you move along the function from the right to x = 2, the y-value you apparoch is y = -2." is the entire answer?

Answer 25

Ugh, this sucks. I gave you the answers, but I don't really have time to explain. I have to go out. .-.
It is impossible for an overall limit to exist. Not lefthand or righthand. Since the function approaches different y-values from the left and right, the overall limit of the function doesn't exist.

Answer 26

lol well thank you none the less c:

Answer 27

Yeah, that's the entire answer.

Answer 28

You're welcome.