Question

Find an equation of the tangent line to the curve at the given point.
y=sin(sinx) (π,0)

Answer 1

\[\Large\rm y=\sin(\sin x),\qquad (\pi,0)\]

Answer 2

Were you able to find a derivative of your function y?

Answer 3

would it be cos^2x(sinx)?

Answer 4

No.\[\Large\rm y'=\cos(\sin x)\cdot \color{royalblue}{\left[\sin x\right]'}\]\[\Large\rm y'=\cos x~ \cos(\sin x)\]Bit of a tricky one to differentiate :)
Understand how I chain ruled there?

Answer 5

yeah i understand how now