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Mathematics 19 Online
OpenStudy (anonymous):

I know this is physics but no one ever answers over there so if anyone could explain to me how to do this I'd appreciate it.

OpenStudy (anonymous):

The following diagram represents a cart with an initial velocity of 1.0 m/s sliding along a frictionless track from point A. Will the cart reach letter E?

OpenStudy (anonymous):

Conservation of energy

OpenStudy (anonymous):

Identify where the cart has potential and where it has kinetic energy and relate to your formulas for each Potential Energy: \[PE = (mass)(gravity)(height)\] Kinetic Energy \[KE = \frac{ 1 }{ 2 }(mass)(velocity)^2\]

OpenStudy (anonymous):

It has potential energy at A, C & E right? and KE at B & D ? @Johnbc

OpenStudy (anonymous):

It has does not have potential energy at C as some of the potential energy from A was converted to B and then all the potential energy was converted to kinetic at C

OpenStudy (anonymous):

no wait, it's the opposite.

OpenStudy (anonymous):

oh ok.

OpenStudy (anonymous):

No you were right the first time just that C was not potential and that B and D have both potential and kinetic energy

OpenStudy (anonymous):

omg marry me! :DD

OpenStudy (anonymous):

ok, but I still don't get how I can figure out if it'll reach E

OpenStudy (anonymous):

By the definition of energy alone you know that energy can not be created nor destroyed so the energy at the top of A must be equal to the energy at the bottom at C and for the cart to be able to reach E the energy at C must be equal to the energy at E

OpenStudy (anonymous):

You are given the variables Mass = 2.0 kg Velocity = 1.0 m/s Height from A to C = 2.5 m Height from C to E = 3.0 m

OpenStudy (anonymous):

nope the cart won't reach point E. Bye

OpenStudy (anonymous):

So it'd be no because it'd require more energy and you can't create energy right? lol

OpenStudy (anonymous):

Correct!! By looking at both heights and knowing energy can not be created you can easily determine if it will reach E or not

OpenStudy (anonymous):

thankkk youuu!! :)

OpenStudy (anonymous):

and thanks @sourwing too i guess lol

OpenStudy (anonymous):

My pleasure

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