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Chemistry 14 Online
OpenStudy (anonymous):

In a group assignment, students are required to fill 10 beakers with 0.720 M CaCl2. If the molar mass of CaCl2 is 11.98 g/mol and each beaker must have 250 mL of solution, what mass of CaCl2 would be used?

OpenStudy (anonymous):

Hi!

OpenStudy (anonymous):

So consider the fact that one of the defined parameters in this question is that we must have 250 ml of solution per 10 bekers, which means that we will have 2500 ml or 2.5 L of solution total

OpenStudy (anonymous):

Does that make sense so far?

OpenStudy (anonymous):

10 beakers * 250 ml solution/beaker = 2500 ml solution

OpenStudy (anonymous):

After this step, we use the molarity to help figure out the amount of moles of CaCl. M = mol/L. 2.5 L solution * (0.72 mol CaCl/L) = 1.8 mol CaCl2 Now, we have to convert mol of CaCl to gram of CaCl2 1.8 mol CaCl2 * (11.98 g/mol) = 21.564 g, or about 21.6 g of CaCl2 Hope this helps!

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