Question

When the sum of a number plus 3 is squared, it is 9 more than the sum of the number plus 2 when squared.

What's the number?

Answer 1

Let the number be x
Sum of a number plus 3 when squared: (x+3)^2
Sum of the number plus 2 when squared: (x+2)^2
9 more than Sum of the number plus 2 when squared: (x+2)^2+9

Hence, the equation becomes,
\[(x+3)^2=(x+2)^2+9\]
Solve it bro, x comes out to be 2 ..!