The square of 9 more than a number is equal to 9 more than the square of the number. What is the number?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
n+9^2=n^2+9? @sid0830
OpenStudy (anonymous):
No bro, it will be
\[(x+9)^2=x^2+9\]
Did you get it?
OpenStudy (anonymous):
Omg, that's the same thing I wrote. Just different variable
OpenStudy (anonymous):
No..I have whole square on LHS..check out yours
OpenStudy (anonymous):
Oh, I see. Okay, now help me work it out. What's the first step.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
kemist's equation is correct
OpenStudy (anonymous):
i dont see square of 'sum'
OpenStudy (anonymous):
Let the number be x
9 more than the number=x+9
Square of 9 more than the number=(x+9)^2
Square of the number=x^2
9 more than square of then number=x^2+9
Put it all together, we get
\[(x+9)^2=x^2+9\]
OpenStudy (anonymous):
We just got that part 10 mins ago. I need to know the first step in how to solve it.
OpenStudy (anonymous):
(x+9)^2=x^2+9
x^2+81+18x=x^2+9
18x=9-81=-72
x=-72/18=-4
Is it clear now?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
x=-4? I got the x^2+81 part but the 18x and such I don't understand.