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OpenStudy (amtran_bus):
\[2t ^{-1/4}\]
OpenStudy (johnweldon1993):
If we need the derivative all we need to do is apply the power rule here
OpenStudy (amtran_bus):
I know that is |dw:1403279651945:dw|
OpenStudy (amtran_bus):
-1/2t?
OpenStudy (anonymous):
-1/2 sqrt (t)
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OpenStudy (amtran_bus):
So anytime it is raised to a fraction power, I need to sqrt? I am self taught in this calc class.
OpenStudy (johnweldon1993):
\[\large nx^{n - 1}\]
So we know that here 'n' = -1/4
So differentiating we have
\[\large -\frac{t^{-\frac{1}{4} - 1}}{2}\]
\[\large -\frac{t^{5/4}}{2}\]
\[\large -\frac{1}{2t^{5/4}}\]
OpenStudy (amtran_bus):
Ohh. Ok. Thanks.
OpenStudy (johnweldon1993):
No not at all!
for derivatives it is actually best to make the square root an exponent as you have here!
OpenStudy (johnweldon1993):
For example...with your original question here...we COULD have
\[\large \frac{2}{\sqrt[4]{t}}\]
But instead, we change that radical to an exponent and make your equation
\[\large 2t^{-1/4}\]
Always easier to make it an exponent
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OpenStudy (johnweldon1993):
Because as you saw...the power rule makes it quick and easy to do