Algebra
15 Online
OpenStudy (anonymous):
Solve the equation or formula for the indicated variable.
S= 5r^2t, for t
A. t= S/5 - r
B. t= 25r/S
C. t=S/5r^2
D. t= r^2- 5S
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OpenStudy (anonymous):
@mathstudent55 ?
OpenStudy (anonymous):
@johnweldon1993
OpenStudy (anonymous):
@cormacpayne
OpenStudy (anonymous):
\[S = 5r^{2t}\]
OpenStudy (anonymous):
What do i do? /.\
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OpenStudy (anonymous):
That's the problem, right? It's not...
\[S = 5r^{2}t\] right?
OpenStudy (anonymous):
Yeah :P
OpenStudy (anonymous):
If the problem is ^ that, then it is \[t = \frac{ S }{ 5r^{2} }\]
OpenStudy (anonymous):
But if it is the first one...
OpenStudy (anonymous):
Its the second one :)
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OpenStudy (anonymous):
Thanks :)
OpenStudy (anonymous):
Okay that makes sense, so it is just a matter of dividing in order to get t by itself on one side
OpenStudy (anonymous):
Can you help me on another one really quick?
OpenStudy (anonymous):
Sure, no problem.
OpenStudy (anonymous):
2|7-7x|= 2x +4 can you solve it? or help me solve it ?
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OpenStudy (anonymous):
Sure, so first let's get the absolute value by itself:
\[\left| 7 - 7x \right| = x + 2\]
OpenStudy (anonymous):
And now, when you want to get rid of the absolute value, you have to set up two equations:
\[7 - 7x = x + 2\]
\[7 - 7x = -(x + 2)\]
OpenStudy (anonymous):
Because you want the right side to equal whatever the absolute value could be, which could be either positive or negative. Does that make sense?
OpenStudy (anonymous):
Yeah? lol so i just solve that ^^
OpenStudy (anonymous):
Yup! Solve both equations for x and you have your answer.
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OpenStudy (anonymous):
5/-8? :)
OpenStudy (anonymous):
Almost!
OpenStudy (anonymous):
Watch out for your sign changes.
OpenStudy (anonymous):
5/8???
OpenStudy (anonymous):
That's one of the solutions! Now you just have to solve the other equation and you're done!
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OpenStudy (anonymous):
5/6?
OpenStudy (anonymous):
3/2?
OpenStudy (anonymous):
Great! Those are your answers!
OpenStudy (anonymous):
Wait so 5/8 and 3/2?
OpenStudy (anonymous):
Yup!
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OpenStudy (anonymous):
okay thanks :) If i need help on another can i message you?
OpenStudy (anonymous):
Sure thing!
OpenStudy (anonymous):
okay :)