How much dry solute would you take to prepare the following solutions from the dry solute and the solvent? 122mL of 0.110M NaNO3. And, 127g of 1.0% NaNO3 solution by mass.

Question

anonymous · Answer

I'll give you a start on the first one. You should try these on your own after that.

Find out how many moles of dry solute you require:
n = 0.122 L x 0.110 mol/L

Once you know how many moles of solute you need, find out the mass of that many moles. That is how much sodium nitrate you would have to dissolve in enough water to prepare 0.122 L of  0.110 M NaNO$_3$.

anonymous · Answer

Thank you for responding! Question, how come you converted mL to L? Are solutions generally moles per liter??

anonymous · Answer

Oh I get it... big M is for molarity.