Question

For what value(s) of k does the graph of g(x) have a normal line whose slope is -1/5 when x = 1?

Answer 1

\[g(x)=k e^{^{2x}} + 3x\]

Answer 2

You can do this without help, right?

Answer 3

well I think I can. I need someone is double check my process and solution

Answer 4

I took the derivative of g(x), then I set it equal to -1/5 and sub x=1

Answer 5

I think k is \[k=\frac{ -8 }{ 3e^2 }\]

Answer 6

I am using what you told me on the previous problem

Answer 7

Derivative gives you slope of tangent, not slope of normal.

Answer 8

so I need to use 5 instead of -1/5

Answer 9

yes

Answer 10

ok give me a moment to work it out

Answer 11

k=1/(e^2)

Answer 12

am I correct?

Answer 13

yes

Answer 14

thanks I appreciate all of your help