Question

need help on solving 3/y+7/2y=13

Answer 1

\[\frac{3}{y}+\frac{7}{2y}=13\] multiply both sides by \(2y\) and start with \(6+7=23y\)

Answer 2

I thought u had to multiply by 2 for 3/y to get the denominator the same

Answer 3

yeah that is why i got \(6\) for the first number, not \(3\)

Answer 4

I did that but what do you do afterwards

Answer 5

also i made a typo
it should be
\[6+7=26y\]

Answer 6

what do you do now?
what is \(6+7\) ?

Answer 7

its 13 but what about the 2y

Answer 8

i see i have confused you
lets start at the beginning
the common denominator for \(\frac{3}{y}\) and \(\frac{7}{2y}\) is \(2y\)

Answer 9

yeah

Answer 10

start with your equation \[\frac{3}{y}+\frac{7}{2y}=13\] and multiply both sides by \(2y\) cancelling as you go

Answer 11

\[2y(\frac{3}{y}+\frac{7}{2y})=13\times 2y\]

Answer 12

\[2y(\frac{3}{y}+\frac{7}{2y})=13\times 2y\]\[2y\times \frac{3}{y}+2y\times \frac{7}{2y})=13\times 2y\]
\[6+7=26y\]

Answer 13

the 6/2y+7/2y=13 from there I have to multiply by 2y on each side to get rid of it

Answer 14

\[2\cancel y\times \frac{3}{\cancel y}+\cancel{2y}\times \frac{7}{\cancel{2y}}=13\times 2y\\
6+7=26y\]

Answer 15

ok I understand

Answer 16

good!

Answer 17

Can u look at my question please? http://openstudy.com/study#/updates/53a4e625e4b0ffdda15dfaef