Question

solve a/2=a-6/3a-9-1/3

Answer 1

use more parenthesis
\(\frac{a}{2}=\frac{a-6}{3a-9}-\frac{1}{3}\\?\)

Answer 2

your supposed to get two answers which is 1 and 2

Answer 3

do I have it correct?

Answer 4

yeah you do

Answer 5

it is very hard to see what you are asking without the parentheses.

Answer 6

ok

Answer 7

i need help

Answer 8

\(\frac{a}{2}=\frac{a-6}{3a-9}-\frac{1}{3}=\frac{a}{2}=\frac{a-6}{3(a-3)}-\frac{1}{3}\)
so our \(LCM=2*3*(a-3)\) so multiply everything by our \(LCM\) and we get
\(2*3*(a-3)\frac{a}{2}=2*3*(a-3)\frac{a-6}{3(a-3)}-2*3*(a-3)\frac{1}{3}=\\\cancel{2}*3*(a-3)\frac{a}{\cancel{2}}=2*\cancel{3*(a-3)}\frac{a-6}{\cancel{3(a-3)}}-2*\cancel{3}*(a-3)\frac{1}{\cancel{3}}=\\3(a-3)a=2(a-6)-2(a-3)\).

you with me?

Answer 9

yeah

Answer 10

ok \(3(a-3)a=2(a-6)-2(a-3)\iff3a^2-9a=2a-12-2a+6 \iff \\3a^2-9a=-6\iff3a^2-9a+6=0\)

Answer 11

can you solve that?

Answer 12

im not sure I followed that right

Answer 13

could you start from the beginning

Answer 14

to say im confused on the way u set up the problem