Question

LCD of 1/t - 1/t^2+t ?

Answer 1

\(\frac{1}{t}-\frac{1}{t^2+t}\)?

Answer 2

\[\frac{ 1 }{ t }-\frac{ 1 }{ t ^{2} }+t\]Which is it? These are two very different things!

Answer 3

the first one

Answer 4

I recommend factoring a t out of the second denominator there and see if you notice anything that way.

Answer 5

It's quite apparent when you do that.

Answer 6

\(\frac{1}{t}-\frac{1}{t^2+t}=\frac{1}{t}-\frac{1}{t(t+1)}\) one term had t, the other haas t(t+1). so its lcm = t(t+1)

Answer 7

yah that's what I did... btw thanks :)