the root x+1 has a multiplicity of 3 for the function x^3-x^2-x+1 true or false
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OpenStudy (anonymous):
that's supposed to be x=1
OpenStudy (anonymous):
The root is x = 1?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Do you know how to factor this?
OpenStudy (anonymous):
uhh not really
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OpenStudy (anonymous):
Okay, do you know what a root is?
OpenStudy (anonymous):
yeah kinda
OpenStudy (anonymous):
What is the root of (x + 5)?
OpenStudy (anonymous):
Do you know how to find it?
OpenStudy (anonymous):
@shelbbss
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OpenStudy (anonymous):
sorry yeah its -5
OpenStudy (anonymous):
Cool, so if the factored form of your posted equation is (x - 1)^2(x + 1), what are your roots?
OpenStudy (anonymous):
1 and -1
OpenStudy (anonymous):
Or, more accurate, x = 1 and x = -1. They want the multiplicity of x = 1. The multiplicity is also the power of the factor with the corresponding root, or 0. So if (x - 1)^2 has the required root, and the multiplicity is 2, because the power is 2, then we know that x = 1 has a multiplicity of 2. Therefor, it is false.
OpenStudy (anonymous):
thank youuuuu <3
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OpenStudy (anonymous):
(x + 5)^3 tells us:
The zero of (x + 5) is -5, with a multiplicity of ^3.