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Mathematics 17 Online
OpenStudy (anonymous):

the root x+1 has a multiplicity of 3 for the function x^3-x^2-x+1 true or false

OpenStudy (anonymous):

that's supposed to be x=1

OpenStudy (anonymous):

The root is x = 1?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Do you know how to factor this?

OpenStudy (anonymous):

uhh not really

OpenStudy (anonymous):

Okay, do you know what a root is?

OpenStudy (anonymous):

yeah kinda

OpenStudy (anonymous):

What is the root of (x + 5)?

OpenStudy (anonymous):

Do you know how to find it?

OpenStudy (anonymous):

@shelbbss

OpenStudy (anonymous):

sorry yeah its -5

OpenStudy (anonymous):

Cool, so if the factored form of your posted equation is (x - 1)^2(x + 1), what are your roots?

OpenStudy (anonymous):

1 and -1

OpenStudy (anonymous):

Or, more accurate, x = 1 and x = -1. They want the multiplicity of x = 1. The multiplicity is also the power of the factor with the corresponding root, or 0. So if (x - 1)^2 has the required root, and the multiplicity is 2, because the power is 2, then we know that x = 1 has a multiplicity of 2. Therefor, it is false.

OpenStudy (anonymous):

thank youuuuu <3

OpenStudy (anonymous):

(x + 5)^3 tells us: The zero of (x + 5) is -5, with a multiplicity of ^3.

OpenStudy (anonymous):

No problem buddy. :)

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