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Physics 22 Online
OpenStudy (anonymous):

what is the charge on one chlorine in BeCl2

OpenStudy (goformit100):

Hello, and A Warm Welcome to Open Study!

OpenStudy (anonymous):

how

OpenStudy (abhisar):

Formal charge = No. of valence electrons - No. of non bonding electrons - \(\huge\frac{No. of Bonding electrons}{2}\)

OpenStudy (abhisar):

got it ?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

OpenStudy (abhisar):

???

OpenStudy (anonymous):

its neg 2

OpenStudy (abhisar):

Is the answer -2 or u calculated it -2 ?

OpenStudy (anonymous):

the answer is -2

OpenStudy (abhisar):

@alphadxg

OpenStudy (alphadxg):

The answer is -2? @hanavoehl

OpenStudy (abhisar):

what should be the answer @alphadxg ?

OpenStudy (alphadxg):

formal charge?

OpenStudy (alphadxg):

@Abhisar

OpenStudy (abhisar):

yes formal charge should be 0 i guess. Is the question seeking for formal charge ?

OpenStudy (alphadxg):

|dw:1403406308521:dw| Valance electrons (7) - nonbonding electrons (6) - paired electrong/2 = 0 for Cl If it was asking for something other than the charge, then it would be Cl (-1) Be (+2)

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