Solve the inequality: (x + 3)(x - 5) < 0. A. x < -3 or x > 5 B. x < -5 or x > 3 C. -3 < x < 5 D. -5 < x < 3
c
what about this? Solve the inequality: (x + 3)(x - 5) > 0. A. x < -3 or x > 5 B. x < -5 or x > 3 C. -3 < x < 5 D. -5 < x < 3
a
the sign is flipped?
you have to solve for x first
-3,5
\(\Large (x + 3)(x - 5) < 0\) \(\Large \color{red}{Case \ 1:} \begin{cases} x+3<0 \\ x-5>0 \end{cases}\Leftrightarrow \begin{cases} x<-3 \\ x>5 \end{cases}\) \(\Large \Rightarrow \)No solution \(\Large \color{red}{Case \ 2:}\begin{cases} x+3>0 \\ x-5<0 \end{cases}\Leftrightarrow \begin{cases} x>-3 \\ x<5 \end{cases} \Rightarrow -3<x<5\) Thus, the corect answer is \(\huge \color {blue}{C}\)
look how @JungHyunRan broke it down for you
ah got it, thanks
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