Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

What is the solution of .....

OpenStudy (anonymous):

OpenStudy (anonymous):

@dan815

OpenStudy (dan815):

0 and 16

OpenStudy (anonymous):

\(\Large \sqrt { 2x+4 } -\sqrt { x } =2\\ \Large \Rightarrow \sqrt { 2x+4 } =2+\sqrt { x } \\ \Large \Rightarrow 2x+4=({ 2+\sqrt { x } })^{ 2 }\\ \Large \Rightarrow 2x+4=4+4\sqrt { x } +x\\ \Large \Rightarrow 4\sqrt { x } =x\\ \Large\Rightarrow 16x={ x }^{ 2 }\\ \Large\Rightarrow { x }^{ 2 }-16x=0\\ \Large \Rightarrow \begin{cases} x=0 \\ x=16 \end{cases}\)

OpenStudy (dan815):

plug and check

OpenStudy (anonymous):

Thank you

OpenStudy (dan815):

@JungHyunRan dang that was some fast latex

OpenStudy (dan815):

awesome thanks!

OpenStudy (anonymous):

:) ur welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!