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Use logarithmic differentiation to determine the derivative.
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\[ f(x) = \frac {x^{2} (x-9)^{9} } { (x^2 +5)^{9} }\]
why does your face look like you're suffering from constipation ?
is math really that difficult?
:(
Rude.
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let\[\ln f(x)=\ln\frac{x ^{2}(x-9)^{9} }{(x ^{2}+5)^{9} }\]\[=2lnx+9\ln(x-9)-9\ln(x ^{2}+5)\] \[\frac{ f \prime(x) }{ f(x) }=\frac{ 2 }{ x }+\frac{ 9 }{ x-9 }-\frac{ 18x }{x ^{2}+5 }\]
Please let me know if you need me to simplify further
alright alright i understand so far
thats all?
take the f(x) to the RHS and simplify
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f'(x) = \[ \frac {x^{2} (x-9)^{9} } { (x^2 +5)^{9} }\left( \frac{ 11 }{ x }-\frac{ 18 }{ x^2 +5 } \right)\] @DominicNg I'm having a hard time simplifying
oh wait i think i know what i did
got it, thanks :D
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