An ideal gas in a cubical box having sides of length L exerts a pressure p on the
walls of the box. If all of this gas is put into a box having sides of length 4L without
changing its temperature, the pressure it exerts on the walls of the larger box will be
(a) 1
4
p
(b) 1
16 p
(c) 1
64 p
(d) p
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OpenStudy (anonymous):
a) 1/4p
b) 1/16p
c)1/64p
d)p
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
\[PV=T\]
OpenStudy (anonymous):
isn't PV=nRT
OpenStudy (anonymous):
So if the temperature never changes, we can set the initial equal to the final\[P_{i}V_{i} = P_{f}V_{f}\]
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OpenStudy (anonymous):
It is, but for this problem, we aren't concerned about the number of moles or gas constant because those will be the same as well and will cancel out on each side.
OpenStudy (anonymous):
So just plug in the values given and solve for the final pressure.
OpenStudy (anonymous):
but there isn't any values!
OpenStudy (anonymous):
\[P_{i} = P, V_{i} = L, V_{f} = 4L\]
OpenStudy (anonymous):
so is it a
@cormacpayne
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