Question

Can someone help?

Answer 1

here it is

Answer 2

What does the ( ) mean? for example for A, 2008 choose 1003?

Answer 3

that's how it's written

Answer 4

Permutation? combination? or else?

Answer 5

i think it could be permutation but i'm not sure..i totally forgot in which segment does these types of equations belong.. :/

Answer 6

it's not a combination ..if that helps

Answer 7

:) @dan815 @ikram002p please help.

Answer 8

\[\left(\begin{matrix}n \\ k\end{matrix}\right)= \frac{ n! }{ k!(n-k)! }\]

Answer 9

yup that's it! xD

Answer 10

yeah thats it !
\(\Huge \left(\begin{matrix}2008\\ 1003\end{matrix}\right)= \frac{ 2008! }{ 1003!(1005)! }\)
\(\Huge \left(\begin{matrix}2008\\ 1004\end{matrix}\right)= \frac{ 2008! }{ 1004!(1004)! }\)
\(\Huge \left(\begin{matrix}2008\\ 1005\end{matrix}\right)= \frac{ 2008! }{ 1005!(1003)! }\)

Answer 11

so do i need to apply all of it for each number or?

Answer 12

Yes, apply all of them, take out your calculator and times each of the numbers.!! hihihi good luck

Answer 13

just compare the Denominators

Answer 14

hah! :D

Answer 15

lol,lol,lol LOL,LOL

Answer 16

the answer is a=c<b but how do i calculate that..

Answer 17

should c be bigger than b by this :/

Answer 18

like this
for a :- 1003! 1003 ! (1004*1005)
for b :- 1003 ! 1003! (1004*1004)
for c:- 1003! 1003! (1004 *1005)!

so a=c
and a>b

Answer 19

typo , b>c and b>c

Answer 20

wasn't a (1004*1003)

Answer 21

1005!=1005 *1004 *1003!

Answer 22

do u know how to find n! ?

Answer 23

well if n was 5 it should be 5*4*3*2*1 ..right?! o.O

Answer 24

yeah !

Answer 25

familiar with pascal triangle ?

Answer 26

yea..

Answer 27

and below property :
\[\large \large \binom{n}{r} = \binom{n}{n-r}\]

Answer 28

okay