Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).
y = -one thirdx - 6
y = -one thirdx - 14
y = 3x - 6
y = 3x - 14
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OpenStudy (anonymous):
the line eq. will be y=3x+c
where c is a constant
OpenStudy (anonymous):
to find c sub. by point (4,-2)
in the equation
OpenStudy (anonymous):
what you mean
OpenStudy (anonymous):
the two lines are parallel
then they have the same slopes (3)
OpenStudy (anonymous):
yeah
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OpenStudy (anonymous):
-2=12+c
c=-14
the equation y=3x-14
OpenStudy (anonymous):
can you explain how did you set that up
OpenStudy (anonymous):
please
OpenStudy (anonymous):
first for create line equation by using the slope and a point
that is the rule
y=mx+c
OpenStudy (anonymous):
m=slope
c=y-intercept
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OpenStudy (anonymous):
now you have a point(4,-2)
and you have a line parallel to the required line
OpenStudy (anonymous):
then the slope of the two lines is similar
OpenStudy (anonymous):
the slope of the line =3
OpenStudy (anonymous):
now you have a point =(4,-2)
and m=3
use the rule
(y-(-2))=m(x-4)