Question

Need answer and how its done. (1/x-2)+(2x/(x-2)(x-8))=(x/2(x-8))

Answer 1

\[\left(\begin{matrix}1 \\ x-2\end{matrix}\right) + \left(\begin{matrix}2x \\ (x-2)(x-8)\end{matrix}\right) = \left(\begin{matrix}x \\ 2(x-8)\end{matrix}\right)\]

Answer 2

simplify

Answer 3

x = 4

Answer 4

can you show work? @quietlysinging

Answer 5

@Chrisgoblin use `\(\frac{a}{b}\)` for \(\frac{a}{b}\)

Answer 6

what?

Answer 7

for fractions.

Answer 8

can you just show me how its done please I will fan

Answer 9

`\(\frac{1}{x-2}+\frac{2x}{(x-2)(x-8)}=\frac{x}{x(x-8)}\) `

\(\huge\downarrow\)

\(\frac{1}{x-2}+\frac{2x}{(x-2)(x-8)}=\frac{x}{x(x-8)}\)

Answer 10

you dont need to fan me...

Answer 11

what does \(\frac{1}{x-2}+\frac{2x}{(x-2)(x-8)}=\frac{x}{x(x-8)}\)
mean

Answer 12

nvm

Answer 13

thats the question

Answer 14

I am just showing you how to make this

\[\left(\begin{matrix}1 \\ x-2\end{matrix}\right) + \left(\begin{matrix}2x \\ (x-2)(x-8)\end{matrix}\right) = \left(\begin{matrix}x \\ 2(x-8)\end{matrix}\right)\]

look like this

\[\frac{1}{x-2}+\frac{2x}{(x-2)(x-8)}=\frac{x}{x(x-8)}\]

Answer 15

ok do you know how to answer it though?

Answer 16

oh sure

\(\frac{1}{x-2}+\frac{2x}{(x-2)(x-8)}=\frac{x}{2(x-8)}\)

multiply every term by \(2(x-2)(x-8)\)

and you get

\(2(x-8)+2*2x=x(x-2)\iff 2x-16+4x=x^2-2x \) so \(x^2-8x+16=0\)

Answer 17

ok

Answer 18

is that the answe? z^2-8x+16=0? if it is thanks

Answer 19

well the answer is \((x-4)(x-4)=0 \implies x=4\)