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Mathematics 16 Online
OpenStudy (anonymous):

Math brain teaser!

OpenStudy (anonymous):

At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?

hartnn (hartnn):

lets say there are only 3 people A,B,C then how many handshakes ?

OpenStudy (anonymous):

I know the answer and how to solve it, its just a fun brain teaser :3

hartnn (hartnn):

A with, B and C , thats 2 and B with C, thats 1 so total = 2+1 for 3 people ==== similarly for 'n' people, you get 1+ 2+3+ ... (n-1)

hartnn (hartnn):

which is n(n-1)/2

hartnn (hartnn):

66 = n(n-1)/2 find n i am too lazy to calculate it :P

OpenStudy (anonymous):

Ummm, something like\[ {n\choose 2} = 66 \]

hartnn (hartnn):

n(n-1) = 132 = 11 *12 which obviously gives you n =12

OpenStudy (anonymous):

There were negative 11 people.

hartnn (hartnn):

lol

OpenStudy (ikram002p):

hhh

OpenStudy (anonymous):

12 In general, with n+1 people, the number of handshakes is the sum of the first n consecutive numbers: 1+2+3+ ... + n. Since this sum is n(n+1)/2, we need to solve the equation n(n+1)/2 = 66. This is the quadratic equation n2+ n -132 = 0. Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party. Since 66 is a relatively small number, you can also solve this problem with a hand calculator. Add 1 + 2 = + 3 = +... etc. until the total is 66. The last number that you entered (11) is n.

OpenStudy (anonymous):

@drumminboy918 If I come up one with one, can you solve it?

OpenStudy (anonymous):

Probably not, I am terrible at math. But I will try.

OpenStudy (anonymous):

I have a few more that are really fun!

OpenStudy (ikram002p):

@wio lets be in separate Qn

OpenStudy (anonymous):

What?! @ikram002p ?!

OpenStudy (ikram002p):

i thought ur gonna type a Qn -_- nvm

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