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i^23
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What is \(i^0\)?
The powers of i cycle through themselves every 4 powers. i^1 = sqrt(-1), i^2 = -1, i^3 = -i, i^4 = 1. Then you start over again, i^5 = sqrt(-1), etc. The way to quickly find out any power of i is to take the power you're given and divide it by 4 and check the remainder. So 23/4 leaves you with a remainder of 3. That means i^23 is the same as i^3, so i^23 = -i.
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