15. A metal of unknown atomic mass exists as a trivalent ion. When electrolysed in solution using a current of 367mA for 186 min, 0.736g of the metal was deposited on the cathode. Calculate the atomic mass of metal
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OpenStudy (anonymous):
@thushananth01
OpenStudy (anonymous):
U have been given the current and time, what can you find from that
OpenStudy (anonymous):
coulombs
OpenStudy (anonymous):
0.367 x 11160 =4095.72 C
OpenStudy (anonymous):
is that correct?
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OpenStudy (anonymous):
I coverted the mins into seconds as time is measured in minutes. I converted milliAmps to Amps due to Current been measured in Amps
OpenStudy (anonymous):
yes thats right..Now you can make an equation
\[M^{3+}_{(aq)} + 3e^{-} = M _{(s)}\]
OpenStudy (anonymous):
u know that 1 mol of electron is equal to 96500C right
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so what do i do next??
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OpenStudy (anonymous):
Yes
3 mol of electron gives 1 mol of Metal which means
3 * 96500C = 1 Mol of metal
so
4095.2C gives how mch mole of metal
OpenStudy (anonymous):
ratio :D
OpenStudy (anonymous):
do you divide 96500C by 4095.2C
OpenStudy (anonymous):
Could you show me how to find the ration please?
OpenStudy (anonymous):
ratio*
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OpenStudy (anonymous):
|dw:1403498904356:dw|
OpenStudy (anonymous):
0.014
OpenStudy (anonymous):
yes
u know
Mole = mass / Ar
u know mole, mass! There you go :)
OpenStudy (anonymous):
so thats the answer = 0.014?
OpenStudy (anonymous):
no ur supposed to find Ar
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OpenStudy (anonymous):
use n = mass/Ar where n=no of moles
OpenStudy (anonymous):
52.57 g/mol
OpenStudy (anonymous):
yes thats right
OpenStudy (anonymous):
so thats the answer
OpenStudy (anonymous):
yup
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