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Chemistry 15 Online
OpenStudy (anonymous):

What mass, in grams, of chlorine gas (Cl2) is contained in a 15.5 liter tank at 25.5 degrees Celsius and 1.98 atmospheres? Show all of the work used to solve this problem.

OpenStudy (somy):

alright i'll give you the formula PV=nRT

OpenStudy (anonymous):

Can you check if I have the substitutions correct? (P)= 1.0 atm (V)= 22.4L (n)= ?? (R)= ? (T)= 298.65 K

OpenStudy (somy):

just a sec* brb ok?

OpenStudy (anonymous):

Ok :)

OpenStudy (somy):

22.4 L??

OpenStudy (somy):

its 15.5 L tho

OpenStudy (anonymous):

stp number or something like that? never mind I guess I got confused in that part.

OpenStudy (somy):

yeah u got a bit

OpenStudy (somy):

from your question (P)= 1.98 atm (V)= 15.5 L (n)= ?? (R)= ? (T)= 298.5 K

OpenStudy (somy):

R is constant value which is 8.31

OpenStudy (anonymous):

so it'll always be 8.31?

OpenStudy (somy):

yes

OpenStudy (somy):

when you use PV=nRT i'll tell u needed units P= Pa V= m3 n= mole R= constant 8.31 T= K

OpenStudy (somy):

so convert units where needed

OpenStudy (anonymous):

So P would be 101325?

OpenStudy (somy):

yes that 1atm = 101325Pa , and you are give 1.98 atm

OpenStudy (anonymous):

So it's 200623.5 and V is 0.0155m3

OpenStudy (somy):

good :)

OpenStudy (somy):

now make n as subject and find it n is mole btw

OpenStudy (anonymous):

I got 1.25 for n

OpenStudy (somy):

alright let me check

OpenStudy (somy):

thats right)

OpenStudy (anonymous):

:D is that all to be done for this equation?

OpenStudy (somy):

yes

OpenStudy (somy):

now main part of the question its asking for mass right?

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

Do I use molarity or mass % formula?

OpenStudy (somy):

u know mole formula right?

OpenStudy (anonymous):

isn't it n = mass /Molar mass

OpenStudy (somy):

yup :)

OpenStudy (somy):

so find mass u have Molar mass

OpenStudy (somy):

and u have mole

OpenStudy (anonymous):

so mass is 88.6 g

OpenStudy (somy):

88.75g

OpenStudy (somy):

right basically :) good job)

OpenStudy (anonymous):

Thank you for your help. I'm really starting to understand these questions. I just have trouble understand how to set them up.

OpenStudy (somy):

yeah i see it :)) keep it up))

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