What mass, in grams, of chlorine gas (Cl2) is contained in a 15.5 liter tank at 25.5 degrees Celsius and 1.98 atmospheres? Show all of the work used to solve this problem.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (somy):
alright i'll give you the formula
PV=nRT
OpenStudy (anonymous):
Can you check if I have the substitutions correct?
(P)= 1.0 atm
(V)= 22.4L
(n)= ??
(R)= ?
(T)= 298.65 K
OpenStudy (somy):
just a sec* brb ok?
OpenStudy (anonymous):
Ok :)
OpenStudy (somy):
22.4 L??
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (somy):
its 15.5 L tho
OpenStudy (anonymous):
stp number or something like that? never mind I guess I got confused in that part.
OpenStudy (somy):
yeah u got a bit
OpenStudy (somy):
from your question
(P)= 1.98 atm
(V)= 15.5 L
(n)= ??
(R)= ?
(T)= 298.5 K
OpenStudy (somy):
R is constant value which is 8.31
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so it'll always be 8.31?
OpenStudy (somy):
yes
OpenStudy (somy):
when you use PV=nRT
i'll tell u needed units
P= Pa
V= m3
n= mole
R= constant 8.31
T= K
OpenStudy (somy):
so convert units where needed
OpenStudy (anonymous):
So P would be 101325?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (somy):
yes that 1atm = 101325Pa , and you are give 1.98 atm
OpenStudy (anonymous):
So it's 200623.5 and V is 0.0155m3
OpenStudy (somy):
good :)
OpenStudy (somy):
now make n as subject and find it
n is mole btw
OpenStudy (anonymous):
I got 1.25 for n
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (somy):
alright let me check
OpenStudy (somy):
thats right)
OpenStudy (anonymous):
:D is that all to be done for this equation?
OpenStudy (somy):
yes
OpenStudy (somy):
now main part of the question
its asking for mass right?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Yeah
OpenStudy (anonymous):
Do I use molarity or mass % formula?
OpenStudy (somy):
u know mole formula right?
OpenStudy (anonymous):
isn't it n = mass /Molar mass
OpenStudy (somy):
yup :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (somy):
so find mass
u have Molar mass
OpenStudy (somy):
and u have mole
OpenStudy (anonymous):
so mass is 88.6 g
OpenStudy (somy):
88.75g
OpenStudy (somy):
right basically :) good job)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Thank you for your help. I'm really starting to understand these questions. I just have trouble understand how to set them up.