Question

Calculate the velocity of a 1650 kg satellite that is in a circular orbit of 4.2 x 106m above the surface of a planet, which has a radius 3.95 x 105 m and the period of the orbit is 2.0 hours.

Answer 1

if a satellite is moving in a orbit of radius \(R\) with velocity \(V\) and time period \(T\) then
its time period is given by
\[T=\frac{ 2\pi R }{ V}\]
so velocity will be
\[V= \frac{ 2\pi R }{T }\]

Answer 2

I got 168.6597 is that right?

Answer 3

@sidsiddhartha