Question

In the following reaction, what coefficient will be written before the oxygen molecule (O2) to balance the chemical equation?

_____ C5H12 + _____ O2 _____ CO2 + _____ H2O

Answer 1

@iPwnBunnies

Answer 2

Balance the whole equation, and you'll know. ;-;

Answer 3

Your choices are
2

5

8

11

Answer 4

My choices? .___.

Answer 5

How do I figure them out when none of them have any numbers :(

Answer 6

Yes they do. You should tackle the biggest molecule first, C5H12. 5 Carbon moles make up this, so there has to be 5 Carbon moles on the right side.

Answer 7

I think you're missing an arrow to separate the reactants from the products

Answer 8

it should be
_____ C5H12 + _____ O2 --> _____ CO2 + _____ H2O

Answer 9

1 C5H12 + ___ O2 -> 5 CO2 + ___ H2O

Answer 10

We added the 5 there to balance the carbons. Now, let's balance the H.
There's 12 in the C5H12. So there has to be 12 on the right side.

1 C5H12 + ___ O2 --> 5 CO2 + 6 H2O

Answer 11

Finally, the oxygen. On the right, we have 10 + 6 oxygen moles, so there has to be 16 moles on the left sides.

1 C5H12 + 8 O2 ---> 5 CO2 + 6 H2O

Answer 12

Where did you get 16 from when there's only 12 molecules?

Answer 13

There are 5 moles of CO2. 2 moles of oxygen per CO2. So there are 10 moles of the oxygen in 5 CO2s. And the 6 moles from the 6 moles of H2O.
10 + 6 = 16

Answer 14

We're not balancing the number of "molecules" but rather the number of "atoms" of each element

Answer 15

^^^

Answer 16

I keep saying moles, that's how I think of it. >.<
Easier if you think of it as atoms and molecules.

Answer 17

@iPwnBunnies good job anyways ♥

Answer 18

Lolol. thanks Somy. cx ♥

Answer 19

So do you understand it @lovelyharmonics ?

Answer 20

np ♥ @iPwnBunnies