Question

If sin Θ = negative square root 3 over 2 and π < Θ < 3 pi over 2, what are the values of cos Θ and tan Θ?

cos Θ = negative 1 over 2; tan Θ = square root 3

cos Θ = negative 1 over 2; tan Θ = −1

cos Θ = square root 3 over 4; tan Θ = −2

cos Θ = 1 over 2; tan Θ = square root 3

Answer 1

help @amistre64 @kirbykirby

Answer 2

@mathhelppleease

Answer 3

@andy8150

Answer 4

@kirbykirby

Answer 5

You can try the property:
\(\sin^2\theta+\cos^2\theta = 1\) and then isolate to find \(\cos^2 \theta\)

But you will find two solutions for \(\cos \theta\). But you use the information for the restriction on \(\pi\) to determine which one you are talking about.

Then, you can find \[ \tan\theta = \frac{\sin \theta}{\cos \theta}\]

Answer 6

so what would the answer be

Answer 7

\[ \sin^2\theta+\cos^2\theta = 1\\
\cos^2\theta= 1 - \sin^2\theta \\
\cos \theta=\pm \sqrt{1-\sin^2\theta}\]

Answer 8

\[ \cos \theta = \pm \sqrt{1-\left( \frac{-\sqrt{3}}{2} \right)^2}\]

Answer 9

Is it B

Answer 10

Or D

Answer 11

@kirbykirby

Answer 12

Is It A, B, C or D

Answer 13

@kirbykirby

Answer 14

did you try it?

Answer 15

yea and i got C

Answer 16

not quite

Answer 17

ok ill try again

Answer 18

Is it D

Answer 19

just draw a picture