At constant volume, if the Kelvin temperature of a gas is doubled, the pressure of the gas is halved. A. True B. False
@aprehan :)
I'm going to let you think through this after I give you some helpful information. Since R = PV/nT, if the Temperature is increased (specifically doubled), what do you think must happen to the Pressure?
if my downstairs increases, what must happen to the upstairs in order to keep R constant?
The same thing ? So its false?
if I have 10 = 5/2, then lets say i increase my downstairs 2 into 5, then that means my upstairs of 5 must be increased to 50 in order for my ratio to still be 10 (b/c 50/5 is 10)
Yes it's false
The pressure would also increase (specifically double)
Okay thanks :)
say this is your original 1L/1K=k you now double it to 2L what must the new Temperature in Kelvins be to equal the same constant
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