Upon balancing the equation below, how many moles of sodium cyanide are needed to react completely with 2.6 moles of sulfuric acid? H2SO4 + NaCN -> HCN + Na2SO4 1.3 moles 2.6 moles 3.9 moles 5.2 moles
@iPwnBunnies
First, we have to balance the equation. :3 This one is simple. Can you see it?
It looks like cn and 2so4 are switched c:
Switched? .-. Yah, this is a displacement reaction, but we need the same number of atoms on each side. ;-;
So do I jus make up numbers until it fits?
H-2. H-1 S-1. S-1 O-4. O-4 Na-1. Na-2 C-1. C-1 N-1. N-1 I forgot how to make them match though.....
@iPwnBunnies don't I add 2 to the first part of the second equation. H-2. H-2 S-1. S-1 O-4. O-4 Na-1. Na-2 C-1. C-2 N-1. N-2 And then I add 2 to the front of the first probem H-2. H-2 S-1. S-1 O-4. O-4 Na-2. Na-2 C-2. C-2 N-2. N-2 And then they're even? Did I do that right?... Ten what do I do?
@iPwnBunnies i have to go :c but can you get on tomorrow? And ill finish this with you tomorrow . Tanks c:
@ikram002p
Do you know what to do?
|dw:1403619866618:dw|
2.6?
Join our real-time social learning platform and learn together with your friends!