Under a dilation, triangle XYZ where X(6, 3), Y(-2, 4), and Z(10, -2) becomes triangle X’Y’Z’ where X’(12, 6), Y’(-4, 8), and Z’(20, -4). What is the scale factor for this dilation?
now you are making me think
Good! I think? In this case I guess it's a hard question!
the distance between \((6,3)\) and \((-2,4)\) is \(\sqrt{65}\)
and lo and behold, the distance between \( (12, 6), (-4, 8)\) is \(2\sqrt{65}\) !
guess the "scale factor" is \(2\)
Hm, great effort, but that's not a given answer.
Oh okay!
lol another "given answer"
Yess, okay this one is very similar... Triangle ABC is located at A(-4,5), B (-4, -1), and C(-1,1). A translation of the triangle is located at A’(-7, 3), B’(-7, -3), and C’(-4, -1). How is the triangle translated?
@mathmale
@satellite73
I'd strongly suggest that you draw both triangles. Then choose any one side of one triangle and determine the length of the corresponding side in the other triangle. What is the scale factor involved?
It's translated 3 units left and 2 units down. :D
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