can someone help me learn how to do slope-intercept form? please?
\[y=mx+b\] is slope intercept form, because \(m\) is the slope and \((0,b)\) is the \(y\) intercept
I get that. But, how do i change The equation 2x + 3y = 1,200 into slope intercept form?
i've been stuck on this for a week i'm not good at algebra sorry..
first subtract 2x from each side
2x+3y=1,200 -2x -2x --------------- x+3y=1,198x? this is where im confused how do i subtract 2x from 1,200?
first for the left hand side 2x+3y_2x =??
is that 2x+3y-2x?
2x+3y-2x=3y
the right hand side will be 1200-2x
Okay so the 2x's cancel each other out?
yes right
okay now what do we do??
the equation will be 3y=1200-2x by comparing with y=mx+c the coefficient of y must be 1 how ??
i dont understand im sorry.. :(
y=mx+c 3y=-2x+1200 you have to divide your equation by 3 to get the standard form
\[\frac{ 3y }{ 3 }=\frac{ -2x }{ 3 }+\frac{ 1200 }{ 3 }\]
\[y=\frac{ -2 }{ 3 }x+400\] where slope =-2/3 y-intercept=400
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