Question

can someone please help what are the complex zeros of the polynomial x^2+4x-32

Answer 1

Have you considered the Quadratic Formula?

Answer 2

Have you considered factoring?

Answer 3

Start out with simplifying it
1 Multiply Terms
\(\color{lime}{x^2+4x−32}\)
2 Simplify Exponents
\(\color{lime}{x^2+4x−32}\)

Answer 4

no im not sure how to do that can u show me plesee

Answer 5

@tkhunny could you explain to him

Answer 6

I know how to find the zeros...I am not sure what "complex zeros" are though....

Answer 7

This is funny because I just finished this module in FLVS.
we can factor this problem into (x^2 - 8)(x^2 + 4) and then further into (x - √8)(x + √8)(x^2 + 4). Right away, we can tell 2 of the roots are ±√8 or ±2√2. You may already know the roots of x^2 + 4, but if you don't you can find them with the quadratic formula:

(-b ± √(b^2 - 4ac)) / (2a)
(±√(-4*1*4)) / (2*1)
(±i√16) / 2
±4i / 2
±2i

Thus, we have found all 4 roots. The zeros of the function are x = ±2√2, ±2i.

Answer 8

@AccidentalAiChan u did thanks so much you know what was on the DBA for module 4 u almost done with module 5

Answer 9

Actually, I'm in Module 10. They will just ask you how to use the quadratic formula and the graphing terms.

Answer 10

All zeros are Complex. Just find ALL of them. In this case, there are none that are not Real.

x^2 + 4x - 32 = (x+8)(x-4) and we see x = -8 or x = 4.

If you continue to search for a solution with an "i" in it, you will search for a very long time. There isn't one.

The Quadratic Formula would have found these, as well.

Answer 11

@mathmale can u help

Answer 12

@ParthKohli u know how

Answer 13

i dont understand