Question

cube root of y^19

Answer 1

19/3 =?

Answer 2

what is it becasue thats not it

Answer 3

\( \bf {\color{brown}{ y^{19}\to y^{3+3+3+3+3+3+1}\to y^3y^3y^3y^3y^3y^3y}}
\\ \quad \\
\Large\sqrt[{\color{brown}{ 3}}]{y^{\color{brown}{ 3}}y^{\color{brown}{ 3}}y^{\color{brown}{ 3}}y^{\color{brown}{ 3}}y^{\color{brown}{ 3}}y^{\color{brown}{ 3}}y}\)

Answer 4

I know, but can you answer me 19/3 =? then I guide you the next step??

Answer 5

If you don't want to take my method, it's perfectly ok to me. hihihi.. Good luck

Answer 6

its6.33333

Answer 7

nope, the form or remainder
19/3= 6 remain 1, ok?

Answer 8

thank you

Answer 9

so, exponent 6 "out", and 1 is still "remain"
that means
The method is correct for any root and any exponent, period!!