Question

Which of the following is the vertex of the quadratic equation y = -4(x - 6)^2 + 2?

Answer 1

for \(y=a(x-b)^2+c\) we have that \((b,c)\) is the vertex point.

Answer 2

how do you find c

Answer 3

-6,2

Answer 4

\(y=a(x-b)^2+c \iff y=-4(x-6)^2+2\)

Answer 5

why -6?

Answer 6

notice the form has (x-b) so since you have (x-6) we have b=6

Answer 7

i dont know

Answer 8

if you had (x+6) then b=-6

Answer 9

we want it to be \((\small x\large-\small b)\)

Answer 10

so the answer is (6,2)

Answer 11

ohh

Answer 12

if you had \(-4(x+6)^2+2\) then the answer would be \((-6,2)\)

Answer 13

because for our form to work we need it to be a minus sign, so its \(-4(x-(-6))^2+2\)

Answer 14

do a few more like this and you will get what I'm saying.

Answer 15

thanks