Question

Does anyone have any trig study tips for memorization?

Answer 1

http://www.youtube.com/watch?v=I4mcja8abDc

Answer 2

no

Answer 3

What exactly are you trying to memorize? Additionally what math are you in?

Answer 4

@snackerman, you there?

Answer 5

Yep! I'm in trig with algebra... I'm trying to memorize the parent functions and their graphs at the moment but, looking for any tips that can help with trig!

Answer 6

i think u shouldn't memorize in trig. trig is only a little about memorization. u only need this memorized to do well in trig:

Answer 7

Thanks! I think it's the equations that get me... My prof doesn't allow calculators and I have a terrible memory.

Answer 8

ur welcome.

Answer 9

did u memorize the values in that pdf?

Answer 10

How do they find all those values.....

Answer 11

its simple

Answer 12

That's a lie

Answer 13

Well, let me not get ahead of myself, how do you do it then?

Answer 14

u only find it difficult cuz trig is difficult for u

Answer 15

How'd you come to that conclusion

Answer 16

And how would you go about getting those values then?

Answer 17

they took a unit circle and used a computer to find da x-coordinates of each angle

Answer 18

So you couldn't do it by hand?

Answer 19

its not impossible but its rly hard

Answer 20

i have dem all memorized doe

Answer 21

Well that was my question lol, you made it seem like you could do it by hand

Answer 22

i can but its long

Answer 23

Why would it be relevant to memorize all those values?

Answer 24

to becum a trig expert (like me) u need to memorize all those values

but bcause ur a newbie u need not knoe all dose values

Answer 25

Here, I'll explain the derivation of \(\sin(18^{\circ})\).

Let \(18^{\circ} = \theta\).

Then \(2\theta = 90 - 3\theta\).

Then \(\sin(2\theta) = \sin(90 - 3\theta) = \cos(3\theta)\).

Using identities \(\sin(2\theta) = 2\sin\theta \cos\theta \) and \(\cos(3\theta) = 4\cos^3 \theta - 3\cos\theta\), we have\[2\sin\theta \cos\theta = 4\cos^3 \theta - 3\cos\theta\]\[\Rightarrow 2\sin\theta = 4\cos^2 \theta - 3\]\[\Rightarrow 2\sin\theta = 4 - 4\sin^2 \theta - 3\]Simple quadratic formula stuff now.

Answer 26

Isn't it 4-8sin^2(theta) since cos^2(theta)=1-2sin^2(theta) and the 4 in front distribute

Answer 27

Are you sure? Because it is a well-known fact that\[\sin^2\theta + \cos^2 \theta = 1\]

Answer 28

Oh, nvm, thats cos(2theta)

Answer 29

OK I got \[\Large \frac{ 2\pm \sqrt{20} }{ -8 }\] Now what?

Answer 30

simplify that and take tha answer thats positive cuz sin is positive in tha 1st quadrant ♥

Answer 31

I thought you were lying, lol

Answer 32

im not

im tha trig expert in tha ghetto