Solve for x. log^2(x - 6) + log^2(x - 4) = log^2 x can someone help?
lawl maybe? :)
just need to make sure we know what we're doing :) \[\large \log_2(x-6) + \log_2(x-4) = \log_2 x\] is this it?
yes lol
x = 3, 1 x = 3 no solution those are my answer choices
if you have answer choices, I'd have thought this was easy XD the quickest way to do that is just to substitute~
what do i sub
oh lol
3 and 1. See which works.
i typed it in but idk what im doing really
that's a problem :D Show me what you did, then~
i typed in log(2)(3-6)+log(2)(1-4)
no wonder. are the logs squared or something?
the picture you have up there is the exact problem but idk how to type it in
so none of the answer choices work?
im not sure if i typed it in right and idk if it works or not bc i really dont know what im looking at
@PeterPan you there?
yup. Try it again and be sure.
if it says nonreal answer that means no solution right?
yup
can you check my answers? im taking a pre test and i wanna do good
sure, why not :)
Solve the logarithmic equation. Round answers to the nearest hundredth. 6 + ln x = 8 answer choices are i choose the first one x ≈ 7.39 x ≈ .69 x ≈ 2
@PeterPan lol sorry if im annoying you but im trying to do really good on this pre test
I guess the first is the best choice?
do you know what this would be|dw:1403619922550:dw|
That's what you have calculators for? sorry, there is no way to figure this out without one ^.^
idk how to type it in my calculator :( i have to solve for x
Well use this fact: \[\Large \ln x^p = p\cdot \ln x\]
im still confused lol
i feel like this one is easy lol i feel like im stupid haha
square root is the same as raising to a power of 1/2
ok im starting to get it so whats the answer?
lol i really need the answer its my last question
i made a 75... 5 points away from skippoing an entire lesson
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