Question

Question 1 (Multiple Choice Worth 5 points)

(06.04 MC)

For the line segment whose endpoints are X (1, 2) and Y (6, 7), find the x value for the point located 1 over 3 the distance from X to Y.

3.5

3.3

2.7

2.4

Answer 1

@jcpd910
?

Answer 2

@Abhisar

Answer 3

@-BeYourself20- @Mathhelp123344

Answer 4

Use the following four coordinates to determine which one has a distance of 13 units from point G (13, 2).

(7, 2)

(9, 5)

(6, 7)

(1, 7)

Answer 5

@Kendra1998

Answer 6

I think its C

Answer 7

which one?

Answer 8

@hartnn

Answer 9

2.7

Answer 10

reason?
or is just a guess?

Answer 11

I googled it, sorry

Answer 12

why are you asking me anyway, your smartscore is higher then mine Lol

Answer 13

do you really believe in numbers?
just because i might have more subscribers on youtube then someone else. Does not really mean that my videos are better.

Answer 14

for the 1st one, the formula is
\(\Large x = \dfrac{mx_2 +nx_1}{m+n}\)

Answer 15

where m:n is the ratio.
since you need, 1/3rd distance.
so ratio will be 1:2
m= 1, n=2

Answer 16

um alright, which on is M and which is N?

Answer 17

nvm

Answer 18

x1= 1, x2 =6

Answer 19

so..
x = 1x^2 + 2x^1/1+2?

Answer 20

i'm stuck :/

Answer 21

plug in x1 an d x2 values too

Answer 22

but what does x equal?

Answer 23

x is your answer...you need to find x

Answer 24

\(\Large x = \dfrac{mx_2 +nx_1}{m+n}= \dfrac{1\times 6 +2\times 1}{1+2} =\)

Answer 25

based on what you wrote. it would equal 8/3
8/3 = 2.66666666
which would be 2.7

Answer 26

@Kendra1998
you were right xD :P

Answer 27

yes, but we should know how it is 2.7 :)

Answer 28

yes, thanks for your help ^^
can you help me with the other one?

Answer 29

do you know distance formula ?

Answer 30

Distance between points (x1,y1) and (x2,y2) is
\(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)

Answer 31

what do we plugin for x?

Answer 32

G (13, 2).
x1 = 13,
y1 = 2

Answer 33

where did G come from? i feel like an idiot xD

Answer 34

take each option , one by one
say 1st,
7,2
plug in x2 =7, y2 = 2

see if you get distance = 13

Answer 35

from the question

Answer 36

ahh.

Answer 37

(x1 - 7)^2 + (y1 - 2)^2
is this right so far @hartnn

Answer 38

x1 = 13,
y1 = 2

Answer 39

13 - 7 = 6
6^2 = 36
2-2 = 0
0^2 = 0

so..
36 + 0 = 36

Answer 40

so..
D = 36
I am still lost :(

Answer 41

and sqrt 36 = 6

so it is not 13
so, it is not 1st choice

Answer 42

now try 2nd choice

Answer 43

x1 = 13,
y1 = 2
x2 =9
y2 =5

Answer 44

lol @RedoHawk actually google was right but thanks lol

Answer 45

13-2 = 11
11^2 = 121
9-5 = 4
4^2 = 16
121 + 16 = 137
now what?

Answer 46

@Kendra1998
lol true :P

Answer 47

@hartnn
what answer do we have to end up with?

Answer 48

distance should come to be 13

try this:

(1, 7)

Answer 49

x1 = 13,
y1 = 2
x2 =1
y2 =7

Answer 50

13-2 = 11
11^2 = 121
1 - 6 = -6
-6^2 = 36
121 + 36 = 157
now what? i don't know why i am doing this. Where did 13 come from? this makes no sense :/

Answer 51

you are doing
x1-y1

look at the formula again

its x1-x2

Answer 52

13-1 = 12
12^2 = 144
2 - 7 = -5
-5^2 = 25
144 + 25 = 169

Answer 53

can you just tell me the answer maybe?

Answer 54

you got it!
\(d= \sqrt{169}=13\)

so last choice is the option

Answer 55

correct option**

Answer 56

um okay, thanks ^^
really appreciate it bro :D