Question

Find the centripetal force needed by a 1250 kg car to make a turn of radius 40.0 m at a speed of 25.0 km/h.

Answer 1

So far I have 1250*25.0^2/40.0 is that right?

Answer 2

Centripetal force = mv\(^2\)/r

Answer 3

1250*(7)\(^2\)/40

Answer 4

Where did you get 7?

Answer 5

u need to convert 25 km/hr into m/s

Answer 6

Ohhh okay

Answer 7

got it ?

Answer 8

Yes I do and would you have to convert anything in this problem (If a 1.50 kg mass revolves at the end of a string 0.50 m long, and its tangential speed is 6.0 m/s, calculate the centripetal force.)

Answer 9

The idea is to keep everything in same unit convention. The best is to keep everything in SI units

Answer 10

Okay okay so my answer should 108N right?

Answer 11

The second question have everything in SI units already

Answer 12

yes

Answer 13

Okay thank you its making more sense

Answer 14

Did you know you can give medals to people who help you with questions? Just click the \(\color{blue}{\text{blue "best response" button}}\) to show appreciation for the people who help you.

Answer 15

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