Question

Add or subtract as indicated

Answer 1

\[\frac{ 5x }{ x+1 } + \frac{ 6 }{ x-1 } - \frac{ 10 }{ x^2-1 }\]

...so many fractions!

Answer 2

Woah....

Answer 3

I think it might have to start off with a common denominator e.e

Answer 4

You shoule be able to just combine like terms. yielding: 7x - 14x = -7x. 30xy - (29xy) = 59xy.28y - (25y) = -3y. for a final answer of.7x + 59xy - 3y

Answer 5

You are right about common denominators @AngelCriner

Answer 6

I am so sorry but what ? >.< @trebillings I'm not following...

and @MathLegend I'm not exactly sure how to get that though

Answer 7

\[(x-1)\frac{ 5x }{ x+1 }+(x+1)\frac{ 6 }{ x-1 }-\frac{ 10 }{ (x+1)(x-1) }\]

Answer 8

We need to multiply the first two fractions by what they don't have in the denominator to get them to be common. Do you follow so far? @AngelCriner

Answer 9

Yes

Answer 10

Can you multiply the first two fractions and show me what you get?

Answer 11

\[\frac{ 5x^2-5x }{ x^-1 } + \frac{ 6x+6 }{ x+1 }\]

There's a most definite chance that I am terribly wrong

Answer 12

\[\frac{ 5x ^{2}-5x }{ (x+1)(x-1) }+\frac{ 6x+6 }{ (x+1)(x-1) }-\frac{ 10 }{ (x+1)(x-1) }\]

Answer 13

Make sense? If so, you know what you now can do.

Answer 14

What do you get as a final answer @AngelCriner ?

Answer 15

Don't all of the denominators cancel each other out?

Answer 16

I got \[\frac{ 5x-4 }{ x-1 }\] though

Answer 17

@AngelCriner I love how you always try and you give an answer to what you think it might be. A lot on here does not do that and just wants the answer. You have made a fan.

Answer 18

Awe thank you @MDoodler I'd just rather try to understand what I can since math's already too complex for me lol I'd rather attempt the problem and see where I mess up at so I can try again in the future.

Answer 19

Sorry, yes but I didn't get a denominator... I just got 5x-4 @AngelCriner